20b^2+21b-5=

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Solution for 20b^2+21b-5= equation:


Simplifying
20b2 + 21b + -5 = 0

Reorder the terms:
-5 + 21b + 20b2 = 0

Solving
-5 + 21b + 20b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-5 + -4b)(1 + -5b) = 0

Subproblem 1

Set the factor '(-5 + -4b)' equal to zero and attempt to solve: Simplifying -5 + -4b = 0 Solving -5 + -4b = 0 Move all terms containing b to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -4b = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -4b = 0 + 5 -4b = 0 + 5 Combine like terms: 0 + 5 = 5 -4b = 5 Divide each side by '-4'. b = -1.25 Simplifying b = -1.25

Subproblem 2

Set the factor '(1 + -5b)' equal to zero and attempt to solve: Simplifying 1 + -5b = 0 Solving 1 + -5b = 0 Move all terms containing b to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -5b = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -5b = 0 + -1 -5b = 0 + -1 Combine like terms: 0 + -1 = -1 -5b = -1 Divide each side by '-5'. b = 0.2 Simplifying b = 0.2

Solution

b = {-1.25, 0.2}

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